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Question: Answered & Verified by Expert
A solenoid of \( 1.5 \mathrm{~m} \) length and \( 4.0 \mathrm{~cm} \) diameter has \( 10 \) turns per \( \mathrm{cm} \). A current of \( 5 \) A is flowing through it. The magnetic field induction at axis inside the solenoid is
PhysicsMagnetic Effects of CurrentJEE Main
Options:
  • A \( 2 \pi \times 10^{-7} \) Gauss
  • B \( 2 \pi \times 10^{-5} \) Gauss
  • C \( 2 \pi \times 10^{-5} \mathrm{~T} \)
  • D \( 2 \pi \times 10^{-7} \mathrm{~T} \)
Solution:
1736 Upvotes Verified Answer
The correct answer is: \( 2 \pi \times 10^{-5} \mathrm{~T} \)
Magnetic field inside the solenoid and is given by, 
B=μ0ni=4π×10-7100.15=2π×10-5 T

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