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A solid ball of volume $V$ is dropped in a viscous liquid. It experiences a viscous force $F$. If the solid ball of volume $2 V$ of same material is dropped in the same fluid, then the viscous force acting on it will be
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The correct answer is:
$2 F$
Viscous force, $F=6 \pi \eta r v$
but
$$
v \propto r^{2}
$$
$$
\therefore \quad \begin{array}{lll}
F \propto V & \text { (volume) }
\end{array}
$$
So, on doubling the volume of the ball, the viscous force is doubled.
but
$$
v \propto r^{2}
$$
$$
\therefore \quad \begin{array}{lll}
F \propto V & \text { (volume) }
\end{array}
$$
So, on doubling the volume of the ball, the viscous force is doubled.
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