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A solid sphere of lithium is rotating with angular frequency ' $\omega$ ' about an axis passing through its diameter. If its temperature is raised by $50^{\circ} \mathrm{C}$ then its new angular frequency is $\left(\alpha_{\text {lithium }}=60 \times 10^{-5}{ }^{\circ} \mathrm{C}^{-1}\right)$
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The correct answer is:
$0.94 \omega$
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