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Question: Answered & Verified by Expert

A solid sphere of radius R carries a charge Q+q distributed uniformly over its volume. A very small point like piece of it of mass m gets detached from the bottom of the sphere and falls down vertically under gravity. This piece carries charge q. If it acquires a speed ν when it has fallen through a vertical height y (see figure), then (assume the remaining portion to be spherical)

PhysicsElectrostaticsJEE MainJEE Main 2020 (05 Sep Shift 1)
Options:
  • A v2=yqQ4πϵ0R2ym+g
  • B v2=yqQ4πϵ0R(R+y)m+g
  • C v2=2yQqR4πϵ0(R+y)3m+g
  • D v2=2yqQ4πε0R(R+y)m+g
Solution:
2267 Upvotes Verified Answer
The correct answer is: v2=2yqQ4πε0R(R+y)m+g

By using total energy conservation
ΔKE+(ΔPE)electo +(ΔPE)gravitation =0

12mV2+kQqR+y-kQqR+(-mgy)=0

12mV2=mgy+kQq1R-1R+y;  V2=2gy+2kQqmyR(R+y)

V2=2yqQ4πε0R(R+y)m+g

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