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A solution of copper sulphate $\left(\mathrm{CuSO}_4\right)$ is electrolysed for $10$ minutes with a current of $1.5$ amperes. The mass of copper deposited at the cathode (at. mass of $\mathrm{Cu}=63 \mathrm{u}$ ) is :
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Verified Answer
The correct answer is:
$0.2938 \mathrm{~g}$
$0.2938 \mathrm{~g}$
$\mathrm{W}=\mathrm{Zit}$
where $\mathrm{Z}$ = Electrochemical equivalent
Eq. wt. of copper $=\frac{63}{2}=31.5$
$\begin{aligned}
& \mathrm{Z}=\frac{31.5}{96500} \\
& \mathrm{~W}=\mathrm{Zit}=\frac{31.5}{96500} \times 1.5 \times 10 \times 60=0.2938 \mathrm{~g}
\end{aligned}$
where $\mathrm{Z}$ = Electrochemical equivalent
Eq. wt. of copper $=\frac{63}{2}=31.5$
$\begin{aligned}
& \mathrm{Z}=\frac{31.5}{96500} \\
& \mathrm{~W}=\mathrm{Zit}=\frac{31.5}{96500} \times 1.5 \times 10 \times 60=0.2938 \mathrm{~g}
\end{aligned}$
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