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Question: Answered & Verified by Expert
A solution of sucrose (molar mass =342 gmol-1 ) has been prepared by dissolving 68.5 g of sucrose in 1000 g of water. The freezing point of the solution obtained will be
( Kf for water =1.86 Kkgmol-1 )
ChemistrySolutionsNEET
Options:
  • A -0.570 C
  • B -0.372 C
  • C -0.520 C
  • D +0.372 C
Solution:
2057 Upvotes Verified Answer
The correct answer is: -0.372 C
ΔTf=Kf.wmol.wt.×Wsol.×1000
ΔTf=68.5×1000342×1000×1.86
ΔTf=0.372
F.pt. of solution =0oC-0.372=-0.372C

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