A sound wave of frequency 200 Hz is travelling in air. The speed of sound in the air is 340 m s - 1 . What is the phase difference at a given instant between two points separated by a distance of 85 cm along the direction of propagation?

Question

A sound wave of frequency 200 Hz is travelling in air. The speed of sound in the air is 340 m s - 1 . What is the phase difference at a given instant between two points separated by a distance of 85 cm along the direction of propagation?, π, 2 π, π 2, π 4

MARKS App · Accepted Answer

First find out the value of the wavelength of the given data, here frequency, f = 200 Hz , and speed of the sound wave, v = 340 m s - 1 , it means the wavelength, λ = v f = 340 200 = 1 . 7 m , it means the phase difference, ∆ ϕ = 2 π λ × ∆ x ⇒ ∆ ϕ = 2 π 1 . 7 × 0 . 85 = π

Search any question & find its solution

Looking for more such questions to practice?