Given, a space station is at a height equal to radius of Earth, \( \frac{1}{2} M v_{s}^{2}=\frac{G M m}{(R+h)} \)
Here, \( h=R \) and \( v_{s} \) is velocity of space station
\[
\begin{array}{l}
\Rightarrow \frac{1}{2} M v_{s}^{2}=\frac{G M m}{2 R} \\
\Rightarrow v_{s}=\sqrt{\frac{G M}{R}}
\end{array}
\]
Now, we know that escape velocity is
\[
\begin{array}{l}
v_{e}=\sqrt{\frac{2 G M}{R}}=\sqrt{2} \sqrt{\frac{G M}{2}} \\
\Rightarrow v_{e}=\sqrt{2} v_{s} \\
\text { or } v_{s}=\frac{1}{\sqrt{2}} v_{e}
\end{array}
\]