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Question: Answered & Verified by Expert

A spacecraft which is moving with a speed u relative to the earth in the x-direction enters the gravitational field of a much more massive planet which is moving with a speed 3u in the negative x-direction. The spacecraft exits following the trajectory as shown below.



The speed of the spacecraft with respect to the earth a long time after it has escaped the planet's gravity is given by


PhysicsCenter of Mass Momentum and CollisionKVPYKVPY 2020 (SA)
Options:
  • A u
  • B 4u
  • C 2u
  • D 7u
Solution:
1928 Upvotes Verified Answer
The correct answer is: 7u


from momentum conservation


-mu+m13u=m1v1+mv2  1


from energy conservation


12mu2+12m19u2=12m1v12+12mv22


12mu2+12m13u-v13u+v1=12mv22


from equation (1)


m13u-v1=mv2+u


12mu2+12mv2+u3u+v1=12mv22


as m1>>>m, we can assume v13u


u2+v2+u6u=v22


v2=7u


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