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A spherical portion $A$ of radius $R$ is removed from a solid sphere $B$ of radius $2 R$ such that the centre of the removed portion is same as the centre of the sphere $B$. The ratio of the moments of inertia of the remaining spherical shell and the solid sphere B about the axes passing through their diameters is
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$31: 32$
Angular acceleration, $\alpha=\frac{8}{2}=4 \mathrm{rev} / \mathrm{s}^2$
$\begin{aligned} & \omega_0=0 \\ & \theta=\omega_0 t+\frac{1}{2} \alpha t^2 \\ & =0+\frac{1}{2} \times 4 \times 5^2 \\ & =50 \times 2 \pi \text { radian, } N=\frac{50 \times 2 \pi}{2 \pi}=50\end{aligned}$
$\begin{aligned} & \omega_0=0 \\ & \theta=\omega_0 t+\frac{1}{2} \alpha t^2 \\ & =0+\frac{1}{2} \times 4 \times 5^2 \\ & =50 \times 2 \pi \text { radian, } N=\frac{50 \times 2 \pi}{2 \pi}=50\end{aligned}$
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