Join the Most Relevant JEE Main 2025 Test Series & get 99+ percentile! Join Now
Search any question & find its solution
Question: Answered & Verified by Expert
A spring of spring constant 200 N m-1 has a block of mass 1 kg hanging at its one end and from another end, spring is attached to a ceiling of an elevator. The elevator rising upwards with an acceleration of g3. When acceleration suddenly ceases, then angular velocity and elongation during the time when the elevator is accelerating

PhysicsOscillationsNEET
Options:
  • A 14.14 rad s-1, 0.07 m
     
  • B 13 rad s-1, 0.1 m
  • C 14 rad s-1, 0.05 m
  • D 10 rad s-1, 0.07 m
Solution:
2536 Upvotes Verified Answer
The correct answer is: 14.14 rad s-1, 0.07 m
 
The angular frequency under all circumstances is

ω = k m

   = 2 0 0 1 = 1 4 . 1 4  rad / s



When elevator is moving up, using NLM

                T - mg = mg 3 T = 4 mg 3

This tension elongates the spring by x

              T = kx   ⇒   x = 4 mg 3 k = 0 . 0 7  m

Looking for more such questions to practice?

Download the MARKS App - The ultimate prep app for IIT JEE & NEET with chapter-wise PYQs, revision notes, formula sheets, custom tests & much more.