A stone is thrown vertically upward. When the particle is at a height half of its maximum height, its speed is 10 m s - 1 , then the maximum height attained by the particle is [ g = 10 m s - 2 ]

Question

A stone is thrown vertically upward. When the particle is at a height half of its maximum height, its speed is 10 m s - 1 , then the maximum height attained by the particle is [ g = 10 m s - 2 ], 8 m, 10 m, 15 m, 20 m

MARKS App · Accepted Answer

Let h be the maximum height to be attained by stone The velocity with which particle is thrown u = 2 gh v 2 = u 2 – 2 g H When H = h 2 , u = 2 g h , v = 1 0 m s - 1 1 0 0 = 2 gh - 2 g h 2 ⇒ h = 1 0 m

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