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A straight conductor of length $0.4 \mathrm{~m}$ is moved with a speed of $7 \mathrm{~m} / \mathrm{s}$ perpendicular to the magnetic field of intensity of $0.9 \mathrm{~Wb} / \mathrm{m}^2$. The induced e.m.f. across the conductor will be
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The correct answer is:
$2.52 \mathrm{~V}$
$e=B v l \Rightarrow e=0.9 \times 7 \times 0.4=2.52 \mathrm{~V}$
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