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Question: Answered & Verified by Expert
A student performs an experiment to determine young's modulus of a wire, exactly 2 m long, by searle's method. In a particular reading, the student measures the extension in the length of the wire to be 0.8 mm with an uncertainty of ± 0.05 mm at a load of exactly 1.0 kg. The student also measures the diameter of the wire to be 0.4 mm with an uncertainty of ± 0.01 mm. The young's modulus obtained from the reading is [Take g=9.8 ms-2]
PhysicsUnits and DimensionsJEE Main
Options:
  • A 2.0±0.3×1011 Nm-2
  • B 2.0±0.2×1011 Nm-2
  • C 2.0±0.1×1011 Nm-2
  • D 2.0±0.05×1011 Nm-2
Solution:
2307 Upvotes Verified Answer
The correct answer is: 2.0±0.2×1011 Nm-2
Young's modulus Y=FLAl=4FLπd2l

                                      =41.0×9.82π0.4×10-320.8×10-3

                                      =2.0×1011 Nm-2

Further, YY=2dd+ll

                           Y=2dd+ll Y

                                     =2×0.010.4+0.050.8×2.0×1011

                                    =0.2×1011 Nm-2

Or            Y+Y=2+0.2×1011 Nm-2

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