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A substance of mass \( 49.53 \mathrm{~g} \) occupies \( 1.5 \mathrm{~cm}^{3} \) of volume. The density of the substance (in \( \mathrm{g} \)
\( \left.\mathrm{cm}^{-3}\right) \) with correct number of significant figures is
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\( \left.\mathrm{cm}^{-3}\right) \) with correct number of significant figures is
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The correct answer is:
\( 33.02 \)
Density $=\frac{\text { Mass }}{\text { Volume }}$
Given, mass $=49.53 \mathrm{~g} ;$ volume $=1.5 \mathrm{~cm}^{2}$
Therefore, Density $=\frac{49.53}{1.5} \mathrm{gcm}^{-3}=33.02 \mathrm{gcm}^{-1}$
Given, mass $=49.53 \mathrm{~g} ;$ volume $=1.5 \mathrm{~cm}^{2}$
Therefore, Density $=\frac{49.53}{1.5} \mathrm{gcm}^{-3}=33.02 \mathrm{gcm}^{-1}$
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