A swimming pool has a depth of 22 m and area 700 m 2 . Calculate fractional change Δ v v of water at the bottom of the swimming pool. Given that the bulk modulus of water is 2 . 2 × 10 9 Nm - 2 , g = 10 m s - 2 , and density of water 1000 kg m - 3 .

Question

A swimming pool has a depth of 22 m and area 700 m 2 . Calculate fractional change Δ v v of water at the bottom of the swimming pool. Given that the bulk modulus of water is 2 . 2 × 10 9 Nm - 2 , g = 10 m s - 2 , and density of water 1000 kg m - 3 ., 2 . 2 × 10 - 4, 0 . 7 × 10 - 4, 0 . 31 × 10 - 4, 10 - 4

MARKS App · Accepted Answer

An increase in the pressure at the bottom due to water will be, ∆ P = ρ W g h . Using the concept of bulk modulus, B = - ∆ P V ∆ V ⇒ ∆ V V = ∆ P B = ρ W g h B = 1000 × 10 × 22 2 . 2 × 10 9 = 10 - 4

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