A thermally insulated rigid container of 1 L volume contains a diatomic ideal gas at room temperature. A small paddle installed inside the container is rotated from the outside, such that the pressure rises by 10 5 Pa . The change in internal energy is close to

Question

A thermally insulated rigid container of 1 L volume contains a diatomic ideal gas at room temperature. A small paddle installed inside the container is rotated from the outside, such that the pressure rises by 10 5 Pa . The change in internal energy is close to, zero, 67 J, 150 J, 250 J

MARKS App · Accepted Answer

Change in internal energy of n moles of an ideal gas, when temperature changes by Δ T is Δ U = n · f 2 · R · Δ T = f 2 n R Δ T = f 2 Δ p · V [ ∴ for ideal gas p V = n R T ] Here, f = 5 (gas is diatomic) Δ p = 10 5 Pa , V = 1 L = 10 - 3 m 3 So, Δ U = 5 2 × 10 5 × 10 - 3 = 250 J

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