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A thin hollow sphere of mass $m$ is completely filled with a liquid of mass $m$. When the sphere rolls with a velocity $v$, kinetic energy of the system is (neglect friction)
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$\frac{4}{3} m v^2$
$\begin{aligned} \text { Total energy } & =\mathrm{KE}+\text { rotational } \mathrm{KE} \\ & =\frac{1}{2}(2 m) v^2+\frac{1}{3} m v^2 \\ & =\frac{4}{3} m v^2\end{aligned}$
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