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Question: Answered & Verified by Expert
A thin ring, a disk and an annular cylinder, of same mass $M$, are released from a point $3.6 \mathrm{~m}$ from the ground up an inclined plane of $30^{\circ}$ degree inclination. The ring and the disk have the same radius $R$. Times taken by the ring and disk to reach the ground are in the ratio,
PhysicsRotational MotionJEE Main
Options:
  • A $\sqrt{2}: \sqrt{1.5}$
  • B $\sqrt{1.4}: \sqrt{1.5}$
  • C $\sqrt{1.5}: \sqrt{1.5}$
  • D $\sqrt{1.5}: \sqrt{1.6}$
Solution:
2067 Upvotes Verified Answer
The correct answer is: $\sqrt{2}: \sqrt{1.5}$
$t=\frac{1}{\sin } \theta \sqrt{\frac{2 h}{g}\left[1+\frac{K^2}{R^2}\right]} \Rightarrow t \propto\left(1+\frac{K^2}{R^2}\right)\left|s o, t_1: t_2=\sqrt{2}: \sqrt{1.5}\right|$

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