A thin semicircular conducting ring of the radius R is falling with its plane vertical in a horizontal magnetic induction B → . At the position MNQ, the speed of the ring is v and the potential difference developed across the ring is

Question

A thin semicircular conducting ring of the radius R is falling with its plane vertical in a horizontal magnetic induction B → . At the position MNQ, the speed of the ring is v and the potential difference developed across the ring is, Zero, B π R 2 2 and M is at a higher potential, π B R v and Q is at a higher potential, 2 R B v and Q is at a higher potential

MARKS App · Accepted Answer

Induced motional emf in MNQ is equivalent to the motional emf in an imaginary wire MQ i. e., e M N Q = e M Q = B v l = B v ( 2 R ) [ l = MQ = 2 R ] V Q - V M = v B 2 R Therefore, the potential difference developed across the ring is 2 R B v with Q at a higher potential.

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