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A transverse wave is represented by the equation
$y=y_0 \sin \frac{2 \pi}{\lambda}(v t-k)$
For what value of $\lambda$ is the particle velocity equal to two times the wave velocity
Options:
$y=y_0 \sin \frac{2 \pi}{\lambda}(v t-k)$
For what value of $\lambda$ is the particle velocity equal to two times the wave velocity
Solution:
2804 Upvotes
Verified Answer
The correct answer is:
$\lambda=\pi y_0$
Comparing the given equation of the standard equation of wave
$\begin{aligned} w y_0 & =2 v \\ 2 \pi n y_0 & =2 n \lambda, \\ \lambda & =\pi y_0\end{aligned}$
$\begin{aligned} w y_0 & =2 v \\ 2 \pi n y_0 & =2 n \lambda, \\ \lambda & =\pi y_0\end{aligned}$
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