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A triangular lamina of area $A$ and height $h$ is immersed in a liquid of density ${ }^\rho$ in a vertical plane with its base on the surface of the liquid. The thrust on the lamina is
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The correct answer is:
$\frac{1}{3} A \rho g h$
Thrust on lamina $=$ pressure at centroid $\times$ Area
$=\frac{h \rho g}{3} \times A=\frac{1}{3} A \rho g h$.
$=\frac{h \rho g}{3} \times A=\frac{1}{3} A \rho g h$.
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