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A uniform metal wire of length 'L', mass ' M' and density ' 0 ' is under a tension ' $\mathrm{T}^{\prime}$ '. If the speed of transverse wave along the wire is ' $V^{\prime}$, then area of cross-section of the wire is
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The correct answer is:
$\frac{\mathrm{T}}{\mathrm{V}^{2}} \mathrm{Q}$
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