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A uniformly tapering vessel is filled with a liquid of density $900 \mathrm{~kg} / \mathrm{m}^3$. The force that acts on the base of the vessel due to the liquid is $\left(g=10 \mathrm{~ms}^{-2}\right)$
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The correct answer is:
$7.2 \mathrm{~N}$
Force acting on the base
$F=P \times A=h d g A=0.4 \times 900 \times 10 \times 2 \times 10^{-3}=7.2 \mathrm{~N}$
$F=P \times A=h d g A=0.4 \times 900 \times 10 \times 2 \times 10^{-3}=7.2 \mathrm{~N}$
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