Search any question & find its solution
Question:
Answered & Verified by Expert
A vessel contains $110 \mathrm{~g}$ of water. The heat capacity of the vessel is equal to $10 \mathrm{~g}$ of water. The initial temperature of water in vessel is $10^{\circ} \mathrm{C}$. If $220 \mathrm{~g}$ of hot water at $70^{\circ} \mathrm{C}$ is poured in the vessel, the final temperature neglecting radiation loss, will be
Options:
Solution:
1134 Upvotes
Verified Answer
The correct answer is:
$50^{\circ} \mathrm{C}$
Let final temperature of water be $\theta$ Heat taken $=$ Heat given
$\begin{aligned} & 110 \times 1(\theta-10)+10(\theta-10)=220 \times 1(70-\theta) \\ & \Rightarrow \theta=48.8^{\circ} \mathrm{C} \approx 50^{\circ} \mathrm{C} .\end{aligned}$
$\begin{aligned} & 110 \times 1(\theta-10)+10(\theta-10)=220 \times 1(70-\theta) \\ & \Rightarrow \theta=48.8^{\circ} \mathrm{C} \approx 50^{\circ} \mathrm{C} .\end{aligned}$
Looking for more such questions to practice?
Download the MARKS App - The ultimate prep app for IIT JEE & NEET with chapter-wise PYQs, revision notes, formula sheets, custom tests & much more.