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Question: Answered & Verified by Expert
A vessel of depth $2 \mathrm{~d} \mathrm{~cm}$ is half filled with a liquid of refractive index $\mu_{1}$ and the upper half with a liquid of refractive index $\mu_{2} .$ The apparent depth of the vessel seen perpendicularly is
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Options:
  • A $\left(\frac{\mu_{1} \mu_{2}}{\mu_{1}+\mu_{2}}\right) \mathrm{d}$
  • B $\left(\frac{1}{\mu_{1}}+\frac{1}{\mu_{2}}\right) \mathrm{d}$
  • C $\left(\frac{1}{\mu_{1}}+\frac{1}{\mu_{2}}\right) 2 \mathrm{~d}$
  • D $\left(\frac{1}{\mu_{1} \mu_{2}}\right) 2 \mathrm{~d}$
Solution:
1560 Upvotes Verified Answer
The correct answer is: $\left(\frac{1}{\mu_{1}}+\frac{1}{\mu_{2}}\right) \mathrm{d}$
Apparent depth $=\mathrm{d} / \mu_{1}+\mathrm{d} / \mu_{2}$.

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