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A weight $W$ can be just supported on a rough inclined place by a force $F$ either acting along the plane or horizontally. If $\theta$ is the angle of friction, then $\mathrm{F} / \mathrm{W}$ is
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Verified Answer
The correct answer is:
$\tan \theta$
Angle of friction, is the angle which the resultant of limiting friction and normal reaction makes with the normal reaction.
$\therefore$
$$
\tan \theta=\frac{F}{R}
$$
Or
$$
\frac{F}{W}=\tan \theta
$$
$\therefore$
$$
\tan \theta=\frac{F}{R}
$$
Or
$$
\frac{F}{W}=\tan \theta
$$
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