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Question: Answered & Verified by Expert
According to Graham's Law, the rate of diffusion of $\mathrm{CO}, \mathrm{O}_{2}, \mathrm{~N}_{2}$ and $\mathrm{CO}_{2}$ follows the order:
ChemistryStates of MatterKVPYKVPY 2016 (SA)
Options:
  • A $\mathrm{CO}=\mathrm{N}_{2}>\mathrm{O}_{2}>\mathrm{CO}_{2}$
  • B $\mathrm{CO}=\mathrm{N}_{2}>\mathrm{CO}_{2}>\mathrm{O}_{2}$
  • C $\mathrm{O}_{2}>\mathrm{CO}=\mathrm{N}_{2}>\mathrm{CO}_{2}$
  • D $\mathrm{CO}_{2}>\mathrm{O}_{2}>\mathrm{CO}=\mathrm{N}_{2}$
Solution:
1979 Upvotes Verified Answer
The correct answer is: $\mathrm{CO}=\mathrm{N}_{2}>\mathrm{O}_{2}>\mathrm{CO}_{2}$
$\mathrm{r} \propto \frac{1}{\sqrt{\mathrm{M}}}$ Rate of diffusion decrease with increase in molecular weight Rate of diffusion order
$\mathrm{CO}=\mathrm{N}_{2}>\mathrm{O}_{2}>\mathrm{CO}_{2}$
$(28) \quad(28) \quad(32)\quad(44)$

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