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Actinides exhibit larger number of oxidation state than that of corresponding lanthanides. The reason behind this aspect is
Chemistryd and f Block ElementsJIPMERJIPMER 2016
Options:
  • A lesser energy difference between $5 f$ and $6 d$-orbitals than between $4 f$ and $5 d$-orbitals
  • B larger atomic size of actinides than the lanthanides
  • C more energy difference between $5 f$ and $6 d$ orbitals than between $4 f$ and $5 d$-orbitals
  • D greater reactive nature of the actinides than the lanthanides
Solution:
2761 Upvotes Verified Answer
The correct answer is: lesser energy difference between $5 f$ and $6 d$-orbitals than between $4 f$ and $5 d$-orbitals
Because of lesser energy difference between $5 f$ and $6 d$ orbitals than that between $4 f$ and $5 d$-orbitals actinides exhibit larger number of oxidation state than that of corresponding lanthanides.

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