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Addition of sodium thiosulphate solution to a solution of silver nitrate gives $X$ as white precipitate, insoluble in water but soluble in excess thiosulphate solution to give $Y$. On boiling in water, $Y$ gives $Z . X, Y$ and $Z$ respectively are
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$\mathrm{Ag}_{2} \mathrm{S}_{2} \mathrm{O}_{3} \cdot \mathrm{Na}_{3}\left[\mathrm{Ag}\left(\mathrm{S}_{2} \mathrm{O}_{3}\right)_{2}\right], \mathrm{Ag}_{2} \mathrm{S}$
The sequence of reactions are
Hence, $X=A g_{2} S_{2} O_{3}$
$Y=\mathrm{Na}_{3}\left[\mathrm{Ag}\left(\mathrm{S}_{2} \mathrm{O}_{3}\right)_{2}\right] Z=\mathrm{Ag}_{2} \mathrm{S}$
Hence, $X=A g_{2} S_{2} O_{3}$
$Y=\mathrm{Na}_{3}\left[\mathrm{Ag}\left(\mathrm{S}_{2} \mathrm{O}_{3}\right)_{2}\right] Z=\mathrm{Ag}_{2} \mathrm{S}$
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