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Question: Answered & Verified by Expert
After balancing equation,
\(\mathrm{C}_2 \mathrm{O}_4^{2-}+\mathrm{H}^{+}+\mathrm{MnO}_4^{-} \longrightarrow \mathrm{CO}_2+\mathrm{Mn}^{2+}+\mathrm{H}_2 \mathrm{O}\)
The coefficient of \(\mathrm{CO}_2\) is
ChemistryRedox ReactionsAP EAMCETAP EAMCET 2020 (17 Sep Shift 2)
Options:
  • A 4
  • B 5
  • C 10
  • D 2
Solution:
1186 Upvotes Verified Answer
The correct answer is: 10
\(\begin{aligned}
& a \stackrel{+3}{\mathrm{C}_2} \mathrm{O}_4^{2-}+b \stackrel{+7}{\mathrm{M}} \mathrm{O}_4^{-}+\mathrm{H}^{+} \rightarrow p \stackrel{+4}{\mathrm{CO}_2}+q \mathrm{Mn}^{2+}+\mathrm{H}_2 \mathrm{O} \\
& \text {nf }(4-3) \times 2=2(7-2) \times 1=5 \\
& \text {mole: } \quad 5 \\
\end{aligned}\)
\(\Rightarrow \quad a=5, b=2\)
\(\Rightarrow\) By POAC, for C-atoms: \(2 a=p\)
\(p=2 a=2 \times 5=10\)
(Here, \(n f: n\)-factor or valency factor)

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