Air inside a closed container is saturated with water vapour. The air pressure is $\mathrm{p}$ and the saturated vapour pressure of water is $\bar{p}$. If the mixture is compressed to one half of its volume by maintaining temperature constant, the pressure becomes

Question

Air inside a closed container is saturated with water vapour. The air pressure is $\mathrm{p}$ and the saturated vapour pressure of water is $\bar{p}$. If the mixture is compressed to one half of its volume by maintaining temperature constant, the pressure becomes, $2(\mathrm{p}+\overline{\mathrm{p}})$, $2 \mathrm{p}+\overline{\mathrm{p}}$, $(\mathrm{p}+\overline{\mathrm{p}}) / 2$, $\mathrm{p}+2 \overline{\mathrm{p}}$

MARKS App · Accepted Answer

Hints: $P_f=2 P+\bar{P}$ Saturated vapour pressure will not change if temperature remains constant

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