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Question: Answered & Verified by Expert
$\mathrm{AlCl}_3$ is an electron deficient compound but $\mathrm{AlF}_3$ is not. This is because
ChemistryChemical Bonding and Molecular StructureAP EAMCETAP EAMCET 2021 (23 Aug Shift 2)
Options:
  • A atomic size of $\mathrm{F}$ is smaller than $\mathrm{Cl}$ which makes $\mathrm{AlF}_3$ more covalent
  • B $\mathrm{AlCl}_3$ is a covalent compound while $\mathrm{AlF}_3$ is an ionic compound
  • C $\mathrm{AlCl}_3$ exists as dimer but $\mathrm{AlF}_3$ does not
  • D $\mathrm{Al}$ in $\mathrm{AlCl}_3$ is in $s p^3$ hybrid state but $\mathrm{Al}$ in $\mathrm{AlF}_3$ is in $s p^2$ hybrid state
Solution:
1719 Upvotes Verified Answer
The correct answer is: $\mathrm{AlCl}_3$ is a covalent compound while $\mathrm{AlF}_3$ is an ionic compound
According to Fajan's rule, larger is the size of anion, more is the covalent character. So, $\mathrm{AlCl}_3$ is a covalent, while $\mathrm{AlF}_3$ is ionic, so $\mathrm{AlCl}_3$ is electron deficient but $\mathrm{AlF}_3$ is not.

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