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All possible values of scalar \( \mathrm{k} \) so that the matrix \( \mathrm{A}^{-1} \) - \( \mathrm{kI} \) is singular where \( \mathrm{A}=\left[\begin{array}{lll}1 & 0 & 2 \\ 0 & 2 & 1 \\ 1 & 0 & 0\end{array}\right] \)
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Verified Answer
The correct answer is:
\( -1, \frac{1}{2} \)
|A-1 - kI| = 0
|A|A-1 - kI| = 0 (|A|≠ 0)
|I - kA| = 0
⇒ |A - λ I| = 0 where
=(1 -λ ) (-λ ) (2 - λ ) + 2(0 - (2 - λ )) = 0
= -λ 3 + 3λ 2 - 2λ - 4 + 2λ = 0
= λ 3 - 3λ 2 + 4 = 0 ⇒ λ = 2, 2,-1 λ k =
|A|A-1 - kI| = 0 (|A|
|I - kA| = 0
=(1 -
= -
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