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Question: Answered & Verified by Expert
All possible values of scalar \( \mathrm{k} \) so that the matrix \( \mathrm{A}^{-1} \) - \( \mathrm{kI} \) is singular where \( \mathrm{A}=\left[\begin{array}{lll}1 & 0 & 2 \\ 0 & 2 & 1 \\ 1 & 0 & 0\end{array}\right] \)
MathematicsMatricesJEE Main
Options:
  • A \( \frac{-1}{2}, 1 \)
  • B \( -1, \frac{1}{2} \)
  • C \( \frac{1}{2}, \frac{-1}{2} \)
  • D \( -1,1 \)
Solution:
1614 Upvotes Verified Answer
The correct answer is: \( -1, \frac{1}{2} \)
|A-1 - kI| = 0
|A|A-1 - kI| = 0 (|A| 0)
|I - kA| = 0
I k - A = 0 A - 1 k · I = 0
|A - λI| = 0 where λ = 1 k
= 1 - λ 0 2 0 2 - λ 1 1 0 - λ = 0
=(1 - λ) (-λ) (2 - λ) + 2(0 - (2 - λ)) = 0
= -λ3 + 3λ2 - 2λ - 4 + 2λ = 0
= λ3 - 3λ2 + 4 = 0 λ = 2, 2,-1 λ k = - 1 , 1 2

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