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Question: Answered & Verified by Expert
Aluminum carbide Al4C3 liberates methane on treatment with water. The grams of aluminum carbide required to produce 11.2L of methane under STP conditions is [Given Al=27 ]
ChemistrySome Basic Concepts of ChemistryJEE Main
Options:
  • A 48
  • B 72
  • C 144
  • D 24
Solution:
1014 Upvotes Verified Answer
The correct answer is: 24
Al4C3+12H2O3CH4+4AlOH3
So 67.2L CH4 evolved by 144g Al4C3
11.2L CH4 will be evolved = 144 67.2 ×11.2=24g

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