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Amount of electricity that can deposit $10 \mathrm{k} \mathrm{gm}$ of silver from $\mathrm{AgNO}_3$ solution is
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1 faraday
$\mathrm{Ag}^{+}+\mathrm{e}^{-} \rightarrow$ Ag; $E_{A g}=\frac{\text { Atomic Mass }}{1}=108$
Number of faraday $=\frac{W_{A g}}{E_{A g}}=\frac{108}{108}=1$
Number of faraday $=\frac{W_{A g}}{E_{A g}}=\frac{108}{108}=1$
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