Search any question & find its solution
Question:
Answered & Verified by Expert
An alternating e.m.f. of frequency $v\left(=\frac{1}{2 \pi \sqrt{L C}}\right)$ is applied to a series $L C R$ circuit. For this frequency of the applied e.m.f.
Options:
Solution:
1112 Upvotes
Verified Answer
The correct answer is:
The circuit is at resonance and its impedance is made up only of a reactive part
As we know resonating angular frequency is
$\omega=\frac{1}{\sqrt{\mathrm{LC}}}$
so resonating frequency is
$\mathrm{f}=\frac{1}{2 \pi \sqrt{\mathrm{LC}}}$
so circuit is in resonance and impedence is made up of only resistance part
$\omega=\frac{1}{\sqrt{\mathrm{LC}}}$
so resonating frequency is
$\mathrm{f}=\frac{1}{2 \pi \sqrt{\mathrm{LC}}}$
so circuit is in resonance and impedence is made up of only resistance part
Looking for more such questions to practice?
Download the MARKS App - The ultimate prep app for IIT JEE & NEET with chapter-wise PYQs, revision notes, formula sheets, custom tests & much more.