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An alternating volta ge $E=200 \sqrt{2} \sin (100 t)$ is connected to 1 microfarad capacitor through AC ammeter. The reading of ammeter shall be
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Verified Answer
The correct answer is:
$20 \mathrm{~mA}$
Reading of ammeter $=I_{\mathrm{rms}}=\frac{V_{\mathrm{rms}}}{X_{C}}=\frac{V_{0} \omega C}{\sqrt{2}}$
$$
\begin{array}{l}
=\frac{200 \sqrt{2} \times 100 \times\left(1 \times 10^{-6}\right)}{\sqrt{2}}=2 \times 10^{-2} \mathrm{~A} \\
=20 \mathrm{~mA}
\end{array}
$$
$$
\begin{array}{l}
=\frac{200 \sqrt{2} \times 100 \times\left(1 \times 10^{-6}\right)}{\sqrt{2}}=2 \times 10^{-2} \mathrm{~A} \\
=20 \mathrm{~mA}
\end{array}
$$
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