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An alternating voltage is connected in series with a resistance $R$ and an inductance $L$ If the potential drop across the resistance is $200 \mathrm{~V}$ and across the inductance is $150 \mathrm{~V}$, then the applied voltage is
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$250 \mathrm{~V}$
The applied voltage is given by $V=\sqrt{V_R^2+V_L^2}$ $V=\sqrt{(200)^2+(150)^2}=250 \mathrm{volt}$
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