An aqueous solution contains 5% by mass of urea and 10% by mass of glucose. If K f for water is 1.86 K kg mol − 1 , the freezing point of the solution is

Question

An aqueous solution contains 5% by mass of urea and 10% by mass of glucose. If K f for water is 1.86 K kg mol − 1 , the freezing point of the solution is, − 3.03 K, 3.03 K, − 3.03 o C, 3.03 o C

MARKS App · Accepted Answer

Moles of solute = 5 60 + 10 180 = 25 180 Molality = n × 1000 weight of solvent Molality of solution = 25 × 1000 180 × 85 Δ T f = 25 × 1000 × 1.86 180 × 85 = 3.03 F . P . = 0 − 3.03 o C = − 3.03 o C

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