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An aqueous solution of oxalic acid dihydrate contains its $6.3 \mathrm{~g}$ in $250 \mathrm{ml}$. The volume of $0.1 \mathrm{~N}$ $\mathrm{NaOH}$ required to completely neutralize $10 \mathrm{ml}$ of this solution
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Verified Answer
The correct answer is:
$40 \mathrm{ml}$
$40 \mathrm{ml}$
Normality of oxalic acid solution
$$
=\frac{6.3 \times 1000}{63 \times 250}=0.4 \mathrm{~N}
$$
Now from
$$
\begin{aligned}
& N_1 V_1=N_2 V_2 \\
& 0.4 \times 10=0.1 \times V_2 \\
& V_2=40 \mathrm{~mL}
\end{aligned}
$$
$$
=\frac{6.3 \times 1000}{63 \times 250}=0.4 \mathrm{~N}
$$
Now from
$$
\begin{aligned}
& N_1 V_1=N_2 V_2 \\
& 0.4 \times 10=0.1 \times V_2 \\
& V_2=40 \mathrm{~mL}
\end{aligned}
$$
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