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Question: Answered & Verified by Expert
An electromagnetic wave travelling in the x- direction has frequency of  2×1014 H z  and electric field amplitude of  27 V m1  oscillates in Y-direction. From the options given below, which one describes the magnetic field for this wave?
PhysicsElectromagnetic WavesJEE MainJEE Main 2015 (10 Apr Online)
Options:
  • A Bx, t=(9×10-8 T)j^ sin1.5×10-6 x-2×1014t 
  • B Bx, t=(9×10-8T)i^sin2π1.5×10-8 x-2×1014t 
  • C B x,t=3×10-8Tj^sinx1.5×10-8-2×1014t
  • D B x,t=9×10-8Tk^sin2πx1.5×10-6-2×1014t
Solution:
1808 Upvotes Verified Answer
The correct answer is: B x,t=9×10-8Tk^sin2πx1.5×10-6-2×1014t
When undefined

Then  B = B0sin ( kxωt )

Of light in travelling along i^ then B in either along j ^ or k ^ .

speed of light  C= E0B0 B0= E0C

     B0= 273×108=9 ×10-8 T

also, ω=2π f=2π ×2 ×1014=4 π ×1014

k= ω c = 4π× 10 14 3× 10 8

=( 2π 1.5× 10 6 )

Looking into the option the correct

Answer is B=9×10-8sin2πx1.5×10-6-2×1014tk^

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