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Question: Answered & Verified by Expert
An electromagnetic wave travels in vacuum along zdirection $E=\left(E_1 \hat{i}+E_2 \hat{j}\right) \cos (k z-\omega t)$. Choose the correct options from the following
PhysicsElectromagnetic Waves
Options:
  • A
    The associated magnetic field is given as
    $$
    B=\frac{1}{c}\left(E_1 \hat{i}-E_2 \hat{j}\right) \cos (k z-\omega t)
    $$
  • B
    The associated magnetic field is given as
    $$
    B=\frac{1}{c}\left(E_1 \hat{i}-E_2 \hat{j}\right) \cos (k z-\omega t)
    $$
  • C
    The given electromagnetic field is circularly polarised
  • D
    The given electromagnetic wave is plane polarised
Solution:
1475 Upvotes Verified Answer
The correct answer is:
The given electromagnetic wave is plane polarised
In electromagnetic wave, the electric field vector is
$$
E=\left(E_1 \hat{i}+E_2 \hat{j}\right) \cos (k z-\omega t)
$$
and the associated magnetic field vector,
$$
B=\frac{E}{c}=\frac{E_1 \hat{i}+E_2 \hat{j}}{c} \cos (k z-\omega t)
$$
So, E and B are perpendicular to each other and the propagation of electromagnetic wave is perpendicular to $\mathrm{E}$ as well as $\mathrm{B}$, so the electromagnetic wave plane polarised.

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