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An electron at rest is accelerated by a potential ' $\mathrm{V}_{1}$ ', in uniform magnetic field
experiences a force 'F $1^{\prime}$. When potential is changed to ${ }^{\prime} \mathrm{V}_{2}^{\prime}$ ', the force experienced
by the electron gets doubled. The ratio of $V_{1}$ to $V_{2}$ is
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experiences a force 'F $1^{\prime}$. When potential is changed to ${ }^{\prime} \mathrm{V}_{2}^{\prime}$ ', the force experienced
by the electron gets doubled. The ratio of $V_{1}$ to $V_{2}$ is
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Verified Answer
The correct answer is:
$1: 4$
An electron at rest is accelerated by a potential ' $V_{1}$ ', in uniform field experiences a force ' $F_{1}$ '. When potential is changed to ' $V_{2}$ ', the force experienced by the electron gets doubled. The ratio of $V_{1}$ to $V_{2}$ is $1: 2$.
$\mathrm{F}_{1}=\frac{\mathrm{eV}_{1}}{\mathrm{~d}} 2 \mathrm{F}_{1}=\frac{\mathrm{eV}_{2}}{\mathrm{~d}}$
$\frac{V_{1}}{V_{2}}=\frac{1}{2}$
$\mathrm{F}_{1}=\frac{\mathrm{eV}_{1}}{\mathrm{~d}} 2 \mathrm{F}_{1}=\frac{\mathrm{eV}_{2}}{\mathrm{~d}}$
$\frac{V_{1}}{V_{2}}=\frac{1}{2}$
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