Join the Most Relevant JEE Main 2025 Test Series & get 99+ percentile! Join Now
Search any question & find its solution
Question: Answered & Verified by Expert
An electron of mass me and a proton of mass mP are accelerated through the same potential difference. The ratio of the de-Broglie wavelength associated with the electron to that with the proton is 
PhysicsDual Nature of MatterJEE MainJEE Main 2021 (22 Jul Shift 1)
Options:
  • A mPme
  • B 1
  • C mpme
  • D memp
Solution:
1785 Upvotes Verified Answer
The correct answer is: mpme

KE=eΔV
λe=h2 me(eΔV)
λp=h2 mp(eΔV)

  λeλp=mpme

Looking for more such questions to practice?

Download the MARKS App - The ultimate prep app for IIT JEE & NEET with chapter-wise PYQs, revision notes, formula sheets, custom tests & much more.