An elevator of mass m is connected to a rope which pulls the elevator up with a maximum acceleration equal to a . If the maximum bearable tension in the rope is T , then for a safe journey the minimum diameter of the rope is [ g = acceleration due to gravity]

Question

An elevator of mass m is connected to a rope which pulls the elevator up with a maximum acceleration equal to a . If the maximum bearable tension in the rope is T , then for a safe journey the minimum diameter of the rope is [ g = acceleration due to gravity], 2 m g + a π T 1 2, 4 m g + a π T 1 2, m g + a π T 1 2, m g + a 2 π T 1 2

MARKS App · Accepted Answer

The maximum tension in the rope = m ( g + a ) Stress in the rope = m g + a π r 2 ∴ T = m g + a π r 2 = m g + a π d 2 2 ∴ T = 4 m g + a π d 2 ∴ d 2 = 4 m g + a π T ∴ d = 4 m g + a π T 1 2

Search any question & find its solution

Looking for more such questions to practice?