An energy of 24.6 eV is required to remove one of the electrons from a helium atom. The energy required to remove both electrons from helium atoms is

Question

An energy of 24.6 eV is required to remove one of the electrons from a helium atom. The energy required to remove both electrons from helium atoms is, 38.2 eV, 49.2 eV, 51.8 eV, 79 eV

MARKS App · Accepted Answer

Required energy = I .E 1 + I .E 2 = 24.6 eV after removal of 1 st e − He + form ( H -like), hence Bohr's model applicable. I .E 2 = I .E H × Z 2 = 13.6 × 4 = 54.4 eV So total energy required = 24.6 + 54.4 = 79 eV

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