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An engine develops $10 \mathrm{~kW}$ of power. How much time will it take to lift a mass of $200 \mathrm{~kg}$ to a height of $40 \mathrm{~m}$. $\left(g=10 \mathrm{~m} / \mathrm{sec}^2\right)$
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Verified Answer
The correct answer is:
8 sec
$P=\frac{m g h}{t}=10 \times 10^3 \Rightarrow t=\frac{200 \times 40 \times 10}{10 \times 10^3}=8 \mathrm{sec}$
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