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An equilateral triangle ABC is formed by two Cu rods AB and BC and one Al rod. It is heated in such a way that temperature of each rod increases by ∆T. Find change in the angle ABC. [Coefficient of linear expansion for Cu is α1,Coeff. of linear expansion for Al is α2]
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The correct answer is:
$d\theta =\frac{2\left( {{\alpha }_{1}}-{{\alpha }_{2}} \right)\Delta t}{\sqrt{3}}$
Correct Option is : (C)
$d\theta =\frac{2\left( {{\alpha }_{1}}-{{\alpha }_{2}} \right)\Delta t}{\sqrt{3}}$
$d\theta =\frac{2\left( {{\alpha }_{1}}-{{\alpha }_{2}} \right)\Delta t}{\sqrt{3}}$
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