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An equilateral triangle is made by uniform wires $A B, B C, C A .$ A current $I$ enters at $A$ and leaves from the mid point of $B C$. If the lengths of each side of the triangle is $L,$ the magnetic field $B$ at the centroid $O$ of the triangle is 
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Verified Answer
The correct answer is:
zero
The given situation can be shown as
The magnetic field at centroid $O$ = Magnetic field due to left part + Magnetic field due to right part
$\therefore$
$$
\mathrm{B}=\mathrm{B}_{1}+\mathrm{B}_{2}=0
$$
(: direction of $B$ due to both parts is different of $O$ )
The magnetic field at centroid $O$ = Magnetic field due to left part + Magnetic field due to right part
$\therefore$
$$
\mathrm{B}=\mathrm{B}_{1}+\mathrm{B}_{2}=0
$$
(: direction of $B$ due to both parts is different of $O$ )
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